20x^2=2000

Solution for 20x^2=2000 equation:

20x^2=2000

We move all terms to the left:

20x^2-(2000)=0

a = 20; b = 0; c = -2000;
Δ = b2-4ac
Δ = 02-4·20·(-2000)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400}{2*20}=\frac{-400}{40}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400}{2*20}=\frac{400}{40}
=10
$